Nested loop in elixir

Question

Given these two lists:
l1 = ['a', 'b', 'c'] l2 = ["Foo", "bar", "baz"]
For each item in l1, I want to run a func with each item in l2
something like:
Enum.each(l1, &(fun1(&1, < each_item_in_l2 >)
Is there a short way of doing that?

Read about comprehensions -> elixir-lang.org/getting-started/comprehensions.html, it may help. — NoDisplayName
– NoDisplayName, Commented Jul 30, 2017 at 7:37

narrowtux · Accepted Answer · 2017-07-31 00:33:53Z

6

Yes, you can use comprehension, here's a quick example for iex:

for abc <- ['a', 'b', 'c'], 
    foobar <- ["Foo", "bar", "baz"] do 
  IO.inspect "#{abc} #{foobar}"
end

edited Jul 31, 2017 at 0:33

narrowtux

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answered Jul 30, 2017 at 8:24

bcat

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1 Comment

GavinBrelstaff Over a year ago

l1 |> Enum.each( fn item -> fun1( item, l2 ); end ) is how I'd phrase it

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