PHP Regular Expression HTML

Question

I have a $source var which I get with curl and contains the following commented out string

//"url":"http://lh5.ggpht.com/_EpgGIto9934/TKXKqAw7uFI/AAAAAAAAGrM/PrQiCNyUdEo/8827.jpg","
$regex = "!url/"/:/"(.*)8827/.jpg!U";
preg_match_all($regex, $source, $res);
var_dump($res);

I want to get the http://.....jpg address What am I doing wrong? Thanks

What kind of string is that? Where does it come from? I don't think this needs a Regex — Pekka
– Pekka, Commented Dec 27, 2010 at 16:34
Also for what you were doing wrong: the escaping. It's \ backslash, not /. — mario
– mario, Commented Dec 27, 2010 at 16:44

daniels · Accepted Answer · 2010-12-27 16:37:09Z

4

That looks like json. If that's the case you won't need regular expressions for that. You can just use json_decode

<?php

$s = "//\"url\":\"http://lh5.ggpht.com/_EpgGIto9934/TKXKqAw7uFI/AAAAAAAAGrM/PrQiCNyUdEo/8827.jpg\",\"";

$regex = '/http(.+)\.jpg/';
preg_match($regex, $s, $matches);
echo $matches[0];

?>

answered Dec 27, 2010 at 16:37

daniels

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Brian Clapper · Accepted Answer · 2010-12-27 16:49:06Z

1

<?php
$source = '"url":"http://lh5.ggpht.com/_EpgGIto9934/TKXKqAw7uFI/AAAAAAAAGrM/PrQiCNyUdEo/8827.jpg","';
$regex = '/^.*\/([^\/]+\.jpg).*$/';
preg_match($regex, $source, $res);
print_r($res);
$jpg = $res[1];
?>

answered Dec 27, 2010 at 16:49

Brian Clapper

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Comments

dlock · Accepted Answer · 2010-12-28 11:34:19Z

0

You may use that regex

http.+\....(?=",".+)

That will work for all 3 letters extensions.

edited Dec 28, 2010 at 11:34

answered Dec 27, 2010 at 16:40

dlock

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