jquery load function problem

Question

i have a select box like that

<select name="sehirler_post" id="sehirler_post">

i am getting values via jquery. i know two different ways to get values. first one is :

var sehirler_post = jQuery('select#sehirler_post').attr('value');

second one is:

jQuery('#sehirler_post ').val()

and finally here is my problem, i have something like this:

jQuery("#okay").load("ajax_post_category.php?okay="+id+"");

i would like to use selectbox value instead of id (okay="+id+"). so, i must change +id+ part with select box value. however i can not do it.. i tried to do like that:

jQuery("#okay").load("ajax_post_category.php?okay="+jQuery('#sehirler_post').val()+"");

it did not work. there must be a way, so i can use selectbox value instead of id in my load function. if anyone helps me, ill be so glad.

regards

Rather than state that "it did not work" in your original question, and "it did not work" in response to the answers you've gotten, perhaps you might want to elaborate a bit and describe how it's not working? Are you getting an error? If so, what's the error. The more info you can provide, the greater chance you have of getting the "right" answer. — charliegriefer
– charliegriefer, Commented Dec 28, 2010 at 5:44
I concur. Saying "it didn't work" doesn't work. Perhaps you can debug this trying to build the url outside your load method. Something like url = someString + someValue and then do console.log(url). Tell us what you get — cesarsalazar
– cesarsalazar, Commented Dec 28, 2010 at 6:00

Shakti Singh · Accepted Answer · 2010-12-28 05:46:37Z

2

#selectList is not the id of your select box, hence change it to

jQuery("#okay").load("ajax_post_category.php?okay="+jQuery('#sehirler_post').val()+"");

can you bread it into two line of code and try

var loadUrl="ajax_post_category.php?okay="+jQuery('#sehirler_post').val();
jQuery("#okay").load(loadUrl);

edited Dec 28, 2010 at 5:46

answered Dec 28, 2010 at 5:25

Shakti Singh

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2 Comments

andrew Over a year ago

thanks for your kindly reply. however it did not work. thanks

andrew Over a year ago

no, did not work. however it works if i write ?okay="+5 instead of ?okay="+jQuery.... well, it works if i write a number with my hand. it cant get numbers from select box value via jquery and load the new page. thats my problem.

zsalzbank · Accepted Answer · 2010-12-28 05:24:09Z

0

You want to do somthing like this:

jQuery("#okay").load("ajax_post_category.php?okay=" + jQuery('#sehirler_post :selected').val());

This looks at your select element and finds the child that has been selected (which should only be one). Then it returns the value.

answered Dec 28, 2010 at 5:24

zsalzbank

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Comments

Ben ODay · Accepted Answer · 2010-12-28 05:26:47Z

0

var id = $("#sehirler_post").val();

answered Dec 28, 2010 at 5:26

Ben ODay

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1 Comment

andrew Over a year ago

thanks for your reply. your answer was a clever idea. i tried it, however it did not work.

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