Replace the array values with html image tag in php

Question

I have here an array below:

<?php
print_r( $result ); 
?>

If I am going to execute the code above, it resulted below:

Array
(
[0] => Array
    (
        [id] => 1
        [uploaded_by] => 1
        [image_url] => http://localhost/dir/img_2.jpg
        [work_description] => test
        [date_added] => 2017-08-03 02:12:38
    )

[1] => Array
    (
        [id] => 2
        [uploaded_by] => 1
        [image_url] => http://localhost/dir/img_4.jpg
        [work_description] => test
        [date_added] => 2017-08-03 02:13:04
    )

[2] => Array
    (
        [id] => 3
        [uploaded_by] => 1
        [image_url] => http://localhost/dir/img_2.jpg
        [work_description] => test
        [date_added] => 2017-08-03 02:46:28
    )

[3] => Array
    (
        [id] => 4
        [uploaded_by] => 1
        [image_url] => http://localhost/dir/img_2.jpg
        [work_description] => sdfsdf
        [date_added] => 2017-08-03 02:46:34
    )
)

Now, from the $result array I wanted to change the values of all image_url programmatically using php into an image in html.

example:

http://localhost/dir/img_2.jpg will become

<img src="http://localhost/dir/img_2.jpg"/>

Those values must be changed if I am going to execute the code.

Does anybody know?

what do you want to get after the change ? are you looking for <img src="http://localhost/dir/img_2.jpg"/> ? if yes this is already there. Pls, let us know clearly. — Md. Abutaleb
– Md. Abutaleb, Commented Aug 3, 2017 at 3:17
What is the problem? Loop over array and concatenate strings. Provide what you have already tried. — Jozef Dúc
– Jozef Dúc, Commented Aug 3, 2017 at 5:35

Pablo Cesar Cordova Morales · Accepted Answer · 2017-08-04 01:36:51Z

1

You can put it in a foreach and modify only the part what you want:

foreach($result as $key => $value) {
    $result[$key]['image_url'] = '<img src="'.$value['image_url'].'"/>';
}

print_r($result);

edited Aug 4, 2017 at 1:36

answered Aug 3, 2017 at 3:32

Pablo Cesar Cordova Morales

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2 Comments

smzapp Over a year ago

Although, the image_url is an array and not an object. Therefore, it must be $result[$key]['image_url'] = '<img src="'.$value['image_url'].'"/>'; Just edit though for future reference. thanks

smzapp Over a year ago

Also with the $value->image_url .. Make it an array.. thanks. The person who downvoted my question did not understand it exactly. But thanks pablo because you understood it

mickmackusa · Accepted Answer · 2018-03-15 04:08:00Z

0

You can use a compact syntax and modify the subarray elements by reference:

Code: (Demo)

foreach ($result as &$subarray) {  // & means modify by reference, so you are overwriting the input array, not traversing a copy.
    $subarray['image_url'] = "<img src=\"{$subarray['image_url']}\"/>";
}

var_export($result);

There is no need to declare $key because the foreach is traversing the actual input array, not a copy of the input array. The image_urls are simply overwritten with each iteration.

answered Mar 15, 2018 at 4:08

mickmackusa♦

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