PHP Array to JavaScript Length

Question

I wrote this code:

$userAddresses = $database->getUsers("SELECT * FROM Users");

$address = array();
foreach($userAddresses as $user){
    array_push($address, array("address"=> $user['address'],
                               "zipcode" => $user['zipcode']));
}
$locations = array(
            "locations" => $address
);

$jsonLocations = json_encode($locations);

This code returns this json object:

{"locations":[
             {"address":"Sneekermeer 25","zipcode":"2993 RL"},
             {"address":"Boeier 13","zipcode":"2992 AK"}]}

I want to get the length of this array inside JavaScript. So I did this:

var address = '<?php echo $jsonLocations ?>';

After that I called console.log(address.length); to check the length but some how it counts all the chars (108 I think) in the address variable and returns that as length. address.locations.length also doesn't work.

Could someone help me out?

what do you mean by length? what it should be showed?

zaidysf
– zaidysf

2017-08-03 09:57:31 +00:00
Commented Aug 3, 2017 at 9:57 — zaidysf
– zaidysf, Commented Aug 3, 2017 at 9:57
Note the quotes on your address line. It's a string.

Jonnix
– Jonnix

2017-08-03 09:57:43 +00:00
Commented Aug 3, 2017 at 9:57 — Jonnix
– Jonnix, Commented Aug 3, 2017 at 9:57

Dinesh undefined · Accepted Answer · 2017-08-03 09:58:11Z

2

You can use JSON.parse()

var address = JSON.parse('<?php echo $jsonLocations ?>');

console.log(address.length); //  will give you length;

answered Aug 3, 2017 at 9:58

Dinesh undefined

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1 Comment

georg Over a year ago

If you go this route, you have to double-encode it, see @Geoffrey's post.

Geoffrey · Accepted Answer · 2017-08-03 10:00:28Z

1

Thats because the string needs to be decoded to an object. You can do this one of two ways.

Non recommended:

var address = <?= $jsonLocations ?>;

Or more correctly and safer:

var address = JSON.parse('<?= addslashes(json_encode($jsonLocations)) ?>');

Do not forget the call to addslashes to prevent any single quotes in your array from breaking the javascript string.

answered Aug 3, 2017 at 10:00

Geoffrey

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2 Comments

georg Over a year ago

What's wrong with the first method? Looks better (and safer) to me.

Geoffrey Over a year ago

@georg It can be used to inject Javascript, not just an object, where as the JSON.parse method will not execute any Javascript, but just load the object. It is why it exists at all.

ZombieTfk · Accepted Answer · 2017-08-03 09:59:31Z

0

You can either remove the quotes around var address = '<?php echo $jsonLocations ?>'; (i.e var address = <?php echo $jsonLocations ?>;) or use JSON.parse to parse it as a string to an object.

answered Aug 3, 2017 at 9:59

ZombieTfk

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Comments

Mad Angle · Accepted Answer · 2017-08-03 10:17:20Z

-1

I have tried the below and its working

var address = '{"locations":[{"address":"Sneekermeer 25","zipcode":"2993 RL"},{"address":"Boeier 13","zipcode":"2992 AK"}]}';
address = JSON.parse(address);
console.log(address.locations.length);

edited Aug 3, 2017 at 10:17

answered Aug 3, 2017 at 9:58

Mad Angle

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