Sending multiple data with jquery Ajax in php

Question

I'm unable to understand these answers Question1 Question2 Question3 so posting my question.
I'm sending an Ajax request in PHP file:

$(document).ready(function(){
    $(document).on('click','.show_more',function(){
        var ID = 10;
        var USERID =1;
        $('.show_more').hide();
        $('.loding').show();
        $.ajax({
            type:'POST',
            url:'/ajaxload.php',
            data:'id='+ID & 'user_id=' + USERID,
            success:function(html){
                $('#show_more_main'+ID).remove();
                $('.post_list').append(html);
            }
        }); 
    });
});

while receiving Ajax URL id is received successfully but user_id is not getting received

<?php 
if(isset($_POST["id"]) && ($_POST["user_id"]) && !empty($_POST["id"])){
    echo $_POST["id"];
    echo $_POST["user_id"];
} 
?>

thank you @dlmeetei for improve my questions

Brijesh Patel
– Brijesh Patel

2017-08-06 10:29:06 +00:00
Commented Aug 6, 2017 at 10:29 — Brijesh Patel
– Brijesh Patel, Commented Aug 6, 2017 at 10:29

dlmeetei · Accepted Answer · 2017-08-06 11:23:17Z

3

Replace :

data:'id='+ID & 'user_id=' + USERID,

with:

data: {id:ID, user_id:USERID}

so your code will look like this :

$(document).ready(function(){
    $(document).on('click','.show_more',function(){
        var ID = 10;
        var USERID =1;
        $('.show_more').hide();
        $('.loding').show();
        $.ajax({
            type:'POST',
            url:'/ajaxload.php',
            data: {id:ID, user_id:USERID},
            success:function(html){
                $('#show_more_main'+ID).remove();
                $('.post_list').append(html);
            }
        }); 
    });
});

edited Aug 6, 2017 at 11:23

dlmeetei

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answered Aug 6, 2017 at 5:24

yoeunes

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2 Comments

yoeunes Over a year ago

you welcome @BrijeshPatel and thank as well for acceping the answer

Brijesh Patel Over a year ago

when i send VARCHAR then it's not working like USERID = "us1"; data: {id:ID, user_id:USERID}, this line is right or where i'm missing some step

Nijeesh Joshy · Accepted Answer · 2017-08-06 05:31:11Z

0

pass the data as javascript objects

data:{
  id:ID,
  user_id:USERID
}

answered Aug 6, 2017 at 5:31

Nijeesh Joshy

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2 Comments

Brijesh Patel Over a year ago

when i send VARCHAR then it's not working like USERID = "us1"; data: {id:ID, user_id:USERID}, this line is right or where i'm missing some step please help

Nijeesh Joshy Over a year ago

Could you give a little more info about the problem? @Brijesh Patel

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