11

I have a string like "GoTo: 7018 6453 12654\n" I just want get the number something like this ['7018', '6453', '12654'], I tries regular expression but I can't split string to get just number here is my code:

Sample 1:

splitter = re.compile(r'\D');
match1 = splitter.split("GoTo: 7018 6453 12654\n")

my output is: ['', '', '', '', '', '', '', '', '7018', '6453', '12654', '']

Sample 2:

splitter = re.compile(r'\W');
match1 = splitter.split("GoTo: 7018 6453 12654\n")

my output is: ['GoTo', '', '7018', '6453', '12654', '']
Improve this question

5 Answers 5

Reset to default
15

If all your numbers are positive integers, you can do that without regular expressions by using the isdigit() method:

>>> text = "GoTo: 7018 6453 12654\n"
>>> [token for token in text.split() if token.isdigit()]
['7018', '6453', '12654']
Improve this answer
Sign up to request clarification or add additional context in comments.

7 Comments

+1 for non-re. One could easily throw int(item) in there as well, if this was needed later on.
Did some timeit... If split+isdigit is the base value (it is the fastest), compiled re.findall is 1.5 times slower and uncompliled re.findall 2.5.
This works only if the separator is pure whitespace (for example even "1, 2, 3" would break it)
@6502, true, but you can specify the separator in the first argument to split() if it's not pure whitespace.
It's all about how you read the problem. By "I've a string like" I supposed it wasn't wise to assume a too strict meaning for "like" so in my opinion the separators are everything but digits ("I just want to get the number") and split can't do it... this makes the problem a job for re. Apparently however not using re is a plus for reasons that I don't understand... and now we got anoter wannabe python programmer that will write bad brittle code instead of learning how to use a regexp.
|
7 
>>> re.findall(r'\d+', 'GoTo: 7018 6453 12654\n')
['7018', '6453', '12654']
Improve this answer

Comments

4 
>>> import re
>>> re.findall("[0-9]+", "GoTo: 7018 6453 12654\n")
['7018', '6453', '12654']
>>>
Improve this answer

Comments

2

You can follow your current method in sample 1 along with this code:

filter (lambda a: a != '', match1)
Improve this answer

Comments

1

Try this:

import re
splitter = re.compile(r'\d+')
match1 = splitter.findall("GoTo: 7018 6453 12654\n")
print match1
Improve this answer

Comments

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Start asking to get answers

Find the answer to your question by asking.

Ask question

Explore related questions

See similar questions with these tags.