Python array group count

Question

In Python, I have an array of,

("192.168.1.1","high"),("192.168.1.1","high"),("192.168.1.1","low"),("192.168.1.1","low"),("192.168.1.2","high"),("192.168.1.2","medium")

and I need an output by showing count

("192.168.1.1","high",2),("192.168.1.1","low",2),("192.168.1.2","high",1),("192.168.1.2","medium",1)

anyone please help me

@ChristianDean it will add each element for every item occurrence , for example for ("192.168.1.1","high",2) it will appear two times. — ᴀʀᴍᴀɴ
– ᴀʀᴍᴀɴ, Commented Aug 11, 2017 at 7:15
Note to answers: Please stop answering this question. Questions such as this are to broad and should be closed as such, not answered. See Why would a question that's normally too broad in any other language be okay if it's in Python? for more details. — Chris
– Chris, Commented Aug 11, 2017 at 7:20

stamaimer · Accepted Answer · 2017-08-11 07:18:30Z

6

You can use Counter from collections.

from collections import Counter

l = [("192.168.1.1","high"),("192.168.1.1","high"),("192.168.1.1","low"),("192.168.1.1","low"),("192.168.1.2","high"),("192.168.1.2","medium")]

counter = Counter(l)

result = [(*key, counter[key]) for key in counter]

answered Aug 11, 2017 at 7:18

stamaimer

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Comments

Rahul · Accepted Answer · 2017-08-11 07:14:07Z

1

If you don't care about order:

l = [("192.168.1.1","high"),("192.168.1.1","high"),("192.168.1.1","low"),("192.168.1.1","low"),("192.168.1.2","high"),("192.168.1.2","medium")]

list(set([(*t, l.count(t)) for t in l]))

answered Aug 11, 2017 at 7:14

Rahul

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