How to take multiple standard input in a single line using php command line

Question

like Input is:
3
1 2
2 3
4 5

I have to take those input in given style. Here (1 and 2), (2 and 3) and (4 and 5) have to take in one line as a input.

Here is my code snippet.

 <?php
header('Content-Type: text/plain');

$testCase = (int) fgets(STDIN);

while($testCase--) {
    $myPosition = (int) fgets(STDIN);
    $liftPosition = (int) fgets(STDIN);
}

Implementation in C++

int main()
{
   int testcase, myPos, liftPos;

   cin >> testcase;

   while(testcase--)
   {
      cin >> myPos >> liftPos;
   }
}

So, how can implement the C++ code in PHP ?

This is not a c++ question...

YSC
– YSC

2017-08-11 12:27:50 +00:00
Commented Aug 11, 2017 at 12:27 — YSC
– YSC, Commented Aug 11, 2017 at 12:27

Canis · Accepted Answer · 2017-08-11 11:46:20Z

3

Equivalent in PHP would be:

<?php
header('Content-Type: text/plain');

$testCase = (int) fgets(STDIN);

while($testCase--) {
    $input = fgets(STDIN);
    $inputParts = preg_split("/[\s]+/",$input);
    $myPosition = (int)$inputParts[0];
    $liftPosition = (int)$inputParts[1];
}

This is because the C-type shift operator in your example takes in both numbers as separate numbers. It delimits automatically with the whitespace character. Therefore you need to split the input string in PHP manually.

answered Aug 11, 2017 at 11:46

Canis

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1 Comment

Canis Over a year ago

@TheExtendable You're welcome! Remember to accept correct answers and upvote helpful comments and answers.

The Alpha · Accepted Answer · 2017-08-11 16:46:59Z

Actually, the problem is in the following line:

$myPosition = (int) fgets(STDIN);

Here, the explicit conversion to int is discarding the value after space, so when you give 1 2 as the input in the command line the (int) is turning it into 1 and you are losing the other character.

$arr = [];
$testCase = (int) fgets(STDIN);

while ($testCase--) {
    list($a, $b) = explode(' ', fgets(STDIN));
    $arr[] = $a.' '.$b;
}

print_r($arr);

The above solution works because I've removed the (int) from the beginning of the fgets. Also note that, I'm using list($a, $b) here, which will actually create two variable $a and $b in the current scope so I'm always assuming that, you'll use two separate numbers (i.e: 1 2), otherwise you can use $inputParts = preg_split("/[\s]+/",$input) or something else with explode to form the array from input from console.

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