1

I have an array (a line of an csv file). This array contains the following data (var_dump($rowData)).

array(8) {
  ["Kategorie"]=>
  string(12) "Bio- Bäcker"
  ["Name"]=>
  string(31) "A nice name"
  ["Adresse"]=>
  string(27) "the street 13"
  ["PLZ"]=>
  string(5) "08056"
  ["Ort"]=>
  string(7) "Zwickau"
  ["Tel"]=>
  string(14) "0375/390 xxx"
  ["Mail"]=>
  string(24) "[email protected]"
  ["Website"]=>
  string(27) "http://doktor-xxx.xx/"
}

By getting values by running $rowData['key'] I get an error - but only by the first array key (Kategorie). PHP is telling me, the key doesn't exists.

I tried something around, all other keys are callable, but not the first.

$profileName = $rowData['Name'];
$profileAddress = $rowData['Adresse'];
$profileZip = $rowData['PLZ'];
$profileCity = $rowData['Ort'];
$profilePhone = $rowData['Tel'];
$profileWebsite = $rowData['Website'];
$profileMail = $rowData['Mail'];
$profileCategory = $rowData['Kategorie'];

Just don't know what's wrong with my code...

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32
  • 1
    Try $rowData->Kategorie it might work that way instead Commented Aug 11, 2017 at 15:46
  • 2
    It is an array, not an object! Commented Aug 11, 2017 at 15:48
  • 1
    Maybe you have some hidden character in the key. Try var_dump(array_keys($rowData)) to see if the key length matches what you expect Commented Aug 11, 2017 at 15:49
  • 4
    Kategorie is definitely not 12 characters; looks like a charset discrepancy to me Commented Aug 11, 2017 at 16:00
  • 1
    @yanman1234 No, that refers to "Kategorie", it is a dump of array_keys(.....) (I assume). Commented Aug 11, 2017 at 16:03

1 Answer 1

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2

Actually there are hidden characters in the key name - by running this code, it works:

foreach ($rowData as $key => $value) {
    $newKey = str_replace('?', '', utf8_decode($key));
    $rowData[$newKey] = $value;
}

Maybe not the best solution, but it works (in this case).

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