I wrote the code below:
try:
nums=input("Write a name:")
print (nums)
except ValueError:
print ("You didn't type a name")
The problem is that even the user enter a number the program prints it `
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3 Answers
You can use the function yourstring.isalpha() it will return true if all characters in the string are from the alphabet.
So for your example:
nums = input("write a name:")
if(not nums.isalpha()):
print("you did not write a name!")
return
print(nums)
Comments
You can use the builtin Python function type() to determine the type of a variable.
1 Comment
Chiheb Nexus
The input type will be always an str because,
input() will return always a string.You can use regex like this example:
import re
while True:
try:
name = input('Enter your name: ')
validate = re.findall(r'^[a-zA-Z]+$', name)
if not validate:
raise ValueError
else:
print('You have entered:', validate[0])
break
except ValueError:
print('Enter a valid name!')
2 Comments
zezollo
Isn't this a bit over complicated, unless one wants to ensure only very specific characters have been entered?
Chiheb Nexus
@zezollo the characters must be in the range of
a -> z and A -> Z So, for example foo123 will throw ValueError exception.