Python: Input validation against a float and a string

Question

This code takes the users input and changes it to an integer and then checks if the int is between 0 and 10. I would also like this code to validate the users input against floats and non-numerical strings and loop back if the user enters a bad input. EX: user inputs 3.5 or "ten" and gets an Error and loops again.

 pyramid = int(input("Please enter an integer between 0 and 10 to begin the sequence: "))

while pyramid < 0 or pyramid > 10:
    print("That value is not in the correct range. Please try again.")
    pyramid = int(input("Please enter an integer between 0 and 10 to begin the sequence: "))

Possible duplicate of Python: Analyzing input to see if its an integer, float, or string — Sheldore
– Sheldore, Commented Sep 25, 2018 at 1:23

DerMolly · Accepted Answer · 2018-09-25 01:32:08Z

0

I'd suggest to try to:

loop indefinitely (while 1)
Cast the input to a float, if this succeeds you can check if it has any decimals (pyramid % 1 != 0) and print the appropriate error in this case.
Cast the input to a integer and break the loop, if it is.
print an error that the input is not an integer

while 1:

    str_in = input("Please enter an integer between 0 and 10 to begin the sequence: ")

    try:
        pyramid = float(str_in)
        if(pyramid % 1 != 0):
            print("That value is a float not an integer. Please try again.")
            continue
    except:
        pass

    try:
        pyramid = int(str_in)
        if pyramid >= 0 and pyramid <= 10:
            break
    except:
        pass

    print("That value is a string not an integer. Please try again.")

print("Your value is {}".format(pyramid))

answered Sep 25, 2018 at 1:32

DerMolly

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