java.math.BigDecimal cannot be cast to java.lang.String?

Question

I am trying to add row values of datatype(money) in which zeros after decimal are automatically formed in Jtable like these 55.0000 28.0000 60.0000 20.0000 50.0000

on runtime log showing this error

java.math.BigDecimal cannot be cast to java.lang.String

Here is the code for rows addition from Jtable

        double total = 0;
        for(int i = 0; i<table.getRowCount(); i++){
            double amount = Double.parseDouble((String) table.getValueAt(1, 6) );
            total+=amount;
        }
        totalSum.setText(String.valueOf(total));

*

Is there any way to add float type values??

*

table.getValueAt(1, 6) already returns a BigDecimal, why do you think you need to cast it to String? What's wrong with using BigDecimal.doubleValue()? — Jim Garrison
– Jim Garrison, Commented Aug 15, 2017 at 4:50
You can reliably convert objects to strings using object.toString() (assuming object isn't null). — Andy Turner
– Andy Turner, Commented Aug 15, 2017 at 4:51
Jim Garrison, sir can you please give me a precise solution. — Kamran Ashiq
– Kamran Ashiq, Commented Aug 15, 2017 at 4:53
and, BTW, you're always getting the value of the same cell (1,6). I guess you meant table.getValueAt(i, 6) — Maurice Perry
– Maurice Perry, Commented Aug 15, 2017 at 5:22

Usagi Miyamoto · Accepted Answer · 2017-08-15 05:02:27Z

3

Try something like this:

BigDecimal total = BigDecimal.ZERO;
for (int i = 0; i < table.getRowCount(); ++i) {
    final BigDecimal amount = (BigDecimal)table.getValueAt(i, 6);
    total = total.add(amount);
}
totalSum.setText(total.toString());

answered Aug 15, 2017 at 5:02

Usagi Miyamoto

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Jim Garrison · Accepted Answer · 2017-08-15 04:52:58Z

3

Change

double amount = Double.parseDouble((String) table.getValueAt(1, 6) );

to

double amount = table.getValueAt(1, 6).doubleValue();

There's no need to convert a BigDecimal to String just to make a double.

answered Aug 15, 2017 at 4:52

Jim Garrison

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2 Comments

ajb Over a year ago

@KamranAshiq All the compiler knows is that getValueAt() is an Object. Apparently the method is defined with Object as the return type. If the method will really return a BigDecimal in this case you can cast it to a BigDecimal and then use doubleValue(): ((BigDecimal)table.getValueAt(1,6)).doubleValue(). This only works if the object it returns really is a BigDecimal. It won't convert anything else to a BigDecimal. Instead, you'll get an exception if it's not the right type.

Andy Turner Over a year ago

Yes, but I think you should point out this loses precision: you can do it only with BigDecimal, and not have this issue.

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