PHP loop through ArrayObject

Question

This is the first time I work with ArrayObjects so maybe I didn't understand it 100% but could you please explain me how to loop through them?

This is my code:

$this->plugins = new \ArrayObject(array());
//just for testing...
$this->plugins->plugin1 = "plugin1";
$this->plugins->plugin2 = "plugin2";
$this->plugins->plugin3 = "plugin3";

foreach ($this->plugins as $plugin){
     //never reached
}

$this->plugins->count() returns 0 and $this->plugins->getIterator()->valid(); returns false as well. What do I have to do?

what if you create a simple array using $this->plugins->plugin1 .... — Abdulla Nilam
– Abdulla Nilam, Commented Aug 15, 2017 at 7:04
This would be a way to solve it too, but I would like to know how it works with ArrayObjects to understand and learn it. — Robin Schambach
– Robin Schambach, Commented Aug 15, 2017 at 7:15

Anna Jeanine · Accepted Answer · 2017-08-15 07:08:52Z

4

You have gotten far but this is how it works

// You can already have an array like this
$array = array('Buck','Jerry','Tomas');

$arrayObject = new ArrayObject($array);
// Add new element
$arrayObject->append('Tweety');

// We are getting the iterator of the object
$iterator = $arrayObject->getIterator();

// Simple while loop
while ($iterator->valid()) {
    echo $iterator->current() . "\n";
    $iterator->next();
}

Source

answered Aug 15, 2017 at 7:08

Anna Jeanine

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4 Comments

Robin Schambach Over a year ago

So I have to use the append method in order to make it work? Thank you

Anna Jeanine Over a year ago

@Anubarak Yes! If this solved your problem please accept the answer so it can help others too.

Robin Schambach Over a year ago

Thats what I'm going to do in 4 minutes - I have to wait a little bit :D

von Oak Over a year ago

@Anubak You use append only when you want to add something to object. If you want to iterate through an object, you don't need use append at all.

von Oak · Accepted Answer · 2017-08-15 07:31:03Z

0

Your code is almost ok, only change initialization of variables, so instead plugins->plugin1 = "plugin1", put everything into array("plugin1", ...) on the beginning. So

$plugins = new ArrayObject(array("plugin1", "plugin2", "plugin3"));

foreach ($plugins as $plugin){
    echo $plugin . "<br>";
}

answered Aug 15, 2017 at 7:31

von Oak

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