I have a piece of code that looks like this:
$result = mysql_query($queryc) or die(mysql_error());
if(mysql_num_rows($result) > 0)
{
while($row = mysql_fetch_array($result, MYSQL_ASSOC))
{
echo $row['$field'];
}
}
Say that code was in a function and I wanted to pass $field to the $row[''] how would I accomplish that?
In other words I'm attempting to use $row['$field']; and $field is defined elsewhere
suppose you have this function definition:
function foo($field) {
// from that code you have given
....
echo $row[$field]; // no need of the quotation marks around $field
....
}
You'd not put any quotes around $field... like this:
echo $row[$field];
Variables are not expanded in single quotes; they are only expanded in double quotes or in the heredoc syntax:
When a string is specified in double quotes or with heredoc, variables are parsed within it.
So either use double quotes or, even better, just omit them:
$row[$field]
Single quotes inhibit variable substitution.
echo $row["$field"];
or just
echo $row[$field];
The latter is highly recommended as it does not require PHP to parse $row["$field"] into $row[$field]. Saves you some microtime in each iteration.
$row["$field"] makes sure your key value is a string. But if you're using $row["$field"], please write is as $row["{$field}"] as a standard. Another example: "My name is {$name} and I'm {$age} years old."`
$row["$field"]. I'd seriously doubt you'd find them. This is not really a preference. Without quotes is much better for three reasons: 1. less code to write. 2. less processing 3. less code to understand or possibly misinterpret. Would you ever write $a = "$b";? If not, why would you ever write $row["$field"];?$row["{$field}"] is just completely tortured and over the top.
$row[$field]