Error when transforming numpy array to PIL Image

Question

I have a variable img which is a int64 numpy.array with sizes 28x28. Its content looks like this:

[...]
[  0   0   0   0   0   0   0   0   0   0   0   0   0   0   0   0   0   0
    0   0   0   0   0   0   0   0   0   0]
[  0   0   0   0   0   0   0   0   0  68 154 188 176 254 254 254 254 254
  227 106  17   0   0   0   0   0   0   0]
[...]

I want to convert the array to a PIL image. To do so I call img = Image.fromarray(img, mode='L') but the output I get is only 0s while it is obvious that it shouldn't be like that. I have checked the mode options and seems like L is correct. Also checked other answers inside stackoverflow and couldn't find something that reproduces this particular problem.

L (8-bit pixels, black and white)

Why is this "simple" piece of code given an unexpected behaviour?

Thanks in advance!

You're correct! Thank you so much (it actually makes so much sense) :) — Manuel Lagunas
– Manuel Lagunas, Commented Aug 18, 2017 at 14:49

Manuel Lagunas · Accepted Answer · 2017-08-18 15:19:08Z

1

As @Divakar pointed out, the data types were not coherent.

Just by adding np.uint8() it works:

img = Image.fromarray(np.uint8(img), mode='L')

answered Aug 18, 2017 at 15:19

Manuel Lagunas

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