I am trying to run a bash while loop inside a Python3.6 script. What I have tried so far is:
subprocess.run(args=['while [ <condition> ]; do <command> done;'])
I get the following error:
FileNotFoundError: [Errno 2] No such file or directory
Is there a way to run such a while loop inside Python?
The part that's tripping you up is providing the args as a list. From the documentation:
If the cmd argument to popen2 functions is a string, the command is executed through /bin/sh. If it is a list, the command is directly executed.
This seems to do what you want:
subprocess.run('i=0; while [ $i -lt 3 ]; do i=`expr $i + 1`; echo $i; done', shell=True)
Notice it's specified as a string instead of a list.
Running bash for loop in Python 3.x is very much like running while loop.
#! /bin/bash
for i in */;
do
zip -r "${i%/}.zip" "$i";
done
This will iterate over a path and zip all directories. To run above bash script in Python:
import subprocess
subprocess.run('for i in */; do zip -r "${i%/}.zip" "$i"; done', shell=True)
shell=Truekeyword argument. As is, you are trying to execute a binary with the name of the passed in string`. And note that I have never seen any need for this.whileis no program, it is a bash builtin command. Trybash -c "while ..."['/bin/bash', '-c', ' .. your code ..']. That way you can control stdout and stderr if you need.