regex python + variable

Question

guys i hope you can give me a hand with this:

Im trying to find a match on a variable value: net_card is a string

net_card = salida.read()    
regex = re.compile('([a-z])\w+' % re.escape(net_card))

if i run this code it show me this error:

regex = re.compile('([a-z])\w+' % re.escape(net_card))
TypeError: not all arguments converted during string formatting

I haven't found a way to solve this, even with scape characters.

now if i do this:

net_card = salida.read()

match = re.search('([a-z])\w+', net_card)
whatIWant = match.group(1) if match else None
print whatIWant

it shows me just (e) in the output even when the value of net_card is NAME=ens32.

What do you think is '([a-z])\w+' % re.escape(net_card)? (Hint: It is not what you think, and it is the expression that causes the problem; everything else is irrelevant.) — DYZ
– DYZ, Commented Sep 1, 2017 at 3:26
What are you trying to match ? what did you expect the result to be for NAME=ens32 ? — Ian Kenney
– Ian Kenney, Commented Sep 1, 2017 at 3:28

Zach Gates · Accepted Answer · 2017-09-01 05:42:45Z

2

Your regex, ([a-z])\w+, will match a single character in the range a-z as the first group, and match the rest of the string as [a-zA-Z0-9_]+. Instead, match the two groups of \w+ (which is [a-zA-Z0-9_]+ in evaluation), separated by an equal sign. Here's an expression:

(\w+)=(\w+)

In practice (if you don't care about "NAME"), you can remove the first group and use:

net_card = salida.read() 
match = re.match('\w+=(\w+)', net_card)
print(match.group(1) if match else None)

Which will output ens32.

answered Sep 1, 2017 at 5:42

Zach Gates

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