I would like to write a regex in Python to pull out '28 june 1994' from the string below and convert june to 6:
fur = "missed intake office visit on 28 june 1994 at sierra vista nursing homesuicidal behavior hx of suicidal be"
I have tried:
fur.extract(r'(?P<day>\d?\d)\s(?P<month>\W+)\s(?P<year>\d+)')
june can take multiple forms including: 'jun', 'june', 'june,' 'june;' ect.
You can use this regex:
(\d{2})[\s]([a-zA-Z]+)[\s](\d{4})
This will output of three groups:
first one: is the day.
second one: is the month name.
third one: is the year
output will be:
Full match 30-42 `28 june 1994`
Group 1. 30-32 `28`
Group 2. 33-37 `june`
Group 3. 38-42 `1994`
You can try this:
import re
fur = "missed intake office visit on 28 june 1994 at sierra vista nursing homesuicidal behavior hx of suicidal be"
data = re.search("(?P<day>\d{1,})\s(?P<month>[a-zA-Z]+)\s(?P<year>\d{4})", fur)
print(data.groupdict())
Output:
{'month': 'june', 'day': '28', 'year': '1994'}
You need to change only June or other monthes too? If U need to change only June, i guess it is enough
re.sub("\d{1,}\sjun[\,e\;]?\s\d{4}","6",yourstring)
\W+will match all non-words characters, I'm sure you meant\w+?. Also you want to replace onlyjuneor other months too?