Vim replace pattern with specific condition

Question

I need to replace ;\s*\<do\> with \rdo in Vim. However, I also need to make sure ;\s*\<do\> does not get replaced if there is a Fortran comment symbol ! before it, i.e., in the search patter !.*;\s*\<do\>. For example, ; do in the uncommented line

j=2; do i=1, 10

should be replaced as

j=2
do i=1,10

But ; do in the following commented part should not be replaced,

 k=3 ! j=2; do i=1, 10

How can I do this in vim ? I tried \(!.*\)\@!;\s*\<do\> and it does not work.

I don't think you should ask this question here, superuser may be a better place — Sinapse
– Sinapse, Commented Sep 3, 2017 at 21:19
There is also vi.stackexchange.com but vi(m) questions have always been accepted on SO... — Fredrik Pihl
– Fredrik Pihl, Commented Sep 3, 2017 at 21:21

avivr · Accepted Answer · 2017-09-03 22:31:27Z

3

I edited this answer based on your example:

Try using :g!/<pattern1>/s/<pattern2>/<replacement>/g:

:g!/!.*/s/\v;\s*do/\rdo/g

This does the replacement of pattern2 with replacement only on lines that don't contain pattern1.

Original answer:

The following pattern should do what you requested: /[^*]\{0,1\}\zs;\\s\*\\<do\\>. You can use it to replace it with whatever you want, e.g. %s/<pattern>/\rdo/g.

edited Sep 3, 2017 at 22:31

answered Sep 3, 2017 at 21:28

avivr

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4 Comments

avivr Over a year ago

note the leading / is the search command, not part of the actual regex.

Kevin Powell Over a year ago

This does not work. Maybe I do not phrase my question properly. By !.*;\s*\<do\>, I mean a search pattern. See the updated question.

avivr Over a year ago

sorry, before you added an example it seemed like you were trying to replace literal search patterns.

Kevin Powell Over a year ago

Finally I figured out an alternative way to do the match, \c\(!.*\)\@<!;\s*\<do\>

SergioAraujo · Accepted Answer · 2017-09-04 20:48:35Z

0

:v/!/ s/; /\r/g

:v  .......... global negation (all lines without pattern)
/!/ .......... all lines not containing !
s ............ substitution
; ............ semicolon space
\r ........... Carriage return "Enter"

answered Sep 4, 2017 at 20:48

SergioAraujo

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