PHP XML simple variable problem

Question

I would like to change the 4c050652f0c3e ( of <testimonial id="xxx"> ) to a dynamic variable that it is sent through a form. My variable is $nodeid = $_POST['nodeid']; but i can not replace it right.

This is the code

foreach( $testimonials->xpath("testimonial[@id='4c050652f0c3e']") as $t ) {
  $t->$_POST['tagname'] = $_POST['newname'];
}

This is what I did but it is not right

foreach( $testimonials->xpath("testimonial[@id=$_POST['nodeid']]") as $t ) {
  $t->$_POST['tagname'] = $_POST['newname'];
}

Thank you!

@MrQ.C. no, that's just telling the XPath expression to match anywhere in the document, which is not necessarily what's wanted. — Gordon
– Gordon, Commented Jan 5, 2011 at 15:01

Nanne · Accepted Answer · 2011-01-05 14:55:46Z

1

foreach works on a copy of your array, so this would not work. You could use a different loop (for loop?), or use references to the array

answered Jan 5, 2011 at 14:55

Nanne

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dfilkovi · Accepted Answer · 2011-01-05 14:57:28Z

1

Try this:

foreach( $testimonials->xpath("testimonial[@id='".$_POST['nodeid']."']") as $t ) {
  $t->$_POST['tagname'] = $_POST['newname'];
}

answered Jan 5, 2011 at 14:57

dfilkovi

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Comments

Haim Evgi · Accepted Answer · 2011-06-19 05:10:29Z

0

try add '

foreach( $testimonials->xpath("testimonial[@id='".$_POST['nodeid']]."'") as $t ) {
  $t->$_POST['tagname'] = $_POST['newname'];
}

edited Jun 19, 2011 at 5:10

answered Jan 5, 2011 at 14:57

Haim Evgi

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