Java 8: How to get element at an index from a Stream

Question

I have a stream, I need to get the element at an index in this stream Basically, a fetch on the basis of index of element like in List list.get(index)

Although Holger is correct, do you really want to discard all other elements of the stream? — Andreas
– Andreas, Commented Sep 6, 2017 at 7:23
if you have a Stream that is not ordered (let's say the source is a Set) what would this index mean at all? — Eugene
– Eugene, Commented Sep 6, 2017 at 7:31
@Andreas: it skips them, which implies being not processed in this specific stream operation, but when the source is a collection, you can stream over it as often as you want. The use case has not been described sufficiently to determine whether it is useful or not. — Holger
– Holger, Commented Sep 6, 2017 at 7:39

Mariusz Lotko · Accepted Answer · 2019-09-26 05:44:33Z

5

There is a skip method that abandons access to first N elements https://docs.oracle.com/javase/8/docs/api/java/util/stream/Stream.html#skip-long-

After that you can use limit(1) and you have just one element at specified index.

EDIT: After @Holger answer there's also a possibility to call

stream().skip(index).findFirst()

edited Sep 26, 2019 at 5:44

answered Sep 6, 2017 at 7:25

Mariusz Lotko

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