TypeError: 'int' object is not iterable while reading image size

Question

Code

import cv2
import numpy as np
import sys
import pytesseract
from PIL import Image
reload(sys)
sys.setdefaultencoding('utf-8')


# Read image with opencv
img = cv2.imread("T.jpg")

print img.size
width , height = img.size

Error

   (C:\Users\SACHIN\Anaconda2) D:\>python R6extractor.py
    6220800
    Traceback (most recent call last):
      File "R6extractor.py", line 14, in <module>
        width , height = img.size
    TypeError: 'int' object is not iterable

But when I googled how to get the width and height of the image .Almost every example showed using width,height = image.size .And I went with it .But I am getting this error so I checked the content of image.size and I am getting 6220800.So what am I doing wrong here

Size isn't returning dimensions - you can't unpack an integer with tuple unpacking. Check the method in PIL docs. — theWanderer4865
– theWanderer4865, Commented Sep 11, 2017 at 15:58
effbot.org/imagingbook/image.htm but this and this SO question stackoverflow.com/questions/6444548/… — codefreaK
– codefreaK, Commented Sep 11, 2017 at 16:02

francisco sollima · Accepted Answer · 2017-09-11 16:12:20Z

3

As @theWanderer4865 said in the comments, img.size returns an integer, and you can't unpack it.

What you need to do is:

height, width, channels = img.shape

EDIT

If you wanted to open it using the Image library, the code would be like this:

from PIL import Image

# Read image with Image
img = Image('T.jpg')
img = cv2.imread("T.jpg")

width, height = img.size

edited Sep 11, 2017 at 16:12

answered Sep 11, 2017 at 16:01

francisco sollima

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5 Comments

codefreaK Over a year ago

I will accept this as answer but can you clarify how this works stackoverflow.com/questions/6444548/…

francisco sollima Over a year ago

In that question, and in the documentation, they open the image through the Image.open method. In your code, you're using cv2.imread instead.

codefreaK Over a year ago

so if I use open I can actually use image.size ?

francisco sollima Over a year ago

Edited the answer

Andre Goulart Over a year ago

In short: CV2 returns img.size as integer. PIL returns img.size as (w, h)

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