I have an array of dictionaries of type <Int,String> like this:
[14: "2", 17: "5", 6: "5", 12: "Ali", 11: "0", 2: "4", 5: "It it it", 15: "5", 18: "2", 16: "5", 8: "2", 13: "4", 19: "4", 1: "2", 4: "12-09-2017 - 9:52"]
I need to get the keys alone and save them in a string, and the values alone and save them in another string.
The results should look like that:
string key = "12,17,6,12,11,2,5,15,18,16,8,13,19,1,4"
string values = "2,5,5,Ali,0,4,It it ti,5,2,5,2,4,4,2,12-09-2017 - 9:52"
A dictionary has a keys and a values property which return the
keys/values as a (lazy) collection. For the values you just have
to join them:
let dict = [14: "2", 17: "5", 6: "5", 12: "Ali", 11: "0", 2: "4", 5: "It it it", 15: "5", 18: "2", 16: "5", 8: "2", 13: "4", 19: "4", 1: "2", 4: "12-09-2017 - 9:52"]
let values = dict.values.joined(separator: ",")
// Ali,5,2,It it it,5,0,4,5,4,4,2,12-09-2017 - 9:52,5,2,2
The keys are integers and must be converted to strings first:
let keys = dict.keys.map(String.init).joined(separator: ",")
// 12,17,14,5,15,11,13,16,19,2,18,4,6,8,1
The order is unspecified, but the same for keys and values.
dict.value might be different than the order of dict.keys but they are the same within a given execution.
Try this, this can be refactored I am sure, this is the first logic that hit me.
let dictionary = [14: "2", 17: "5", 6: "5", 12: "Ali", 11: "0", 2: "4", 5: "It it it", 15: "5", 18: "2", 16: "5", 8: "2", 13: "4", 19: "4", 1: "2", 4: "12-09-2017 - 9:52"]
let arrayKeys = dictionary.map({ $0.key})
print(arrayKeys)
var stringValue: String = ""
for value in arrayKeys {
stringValue.append(value.description)
stringValue.append(",")
}
arrayKeys by maping all keys in dictionary? there is dictionary.keys that do exactly what you want.