Extract Number from string into a list in Scala

Question

I have the following string :

var myStr = "abc12ef4567gh90ijkl789"

The size of the list is not fixed and it contains number in between. I want to extract the numbers and store them in the form of a list in this manner:

List(12,4567,90,789)

I tried the solution mentioned here but cannot extend it to my case. I just want to know if there is any faster or efficient solution instead of just traversing the string and extracting the numbers one by one using brute force ? Also, the string can be arbitrary length.

Wiktor Stribiżew · Accepted Answer · 2017-09-12 08:42:41Z

12

It seems you may just collect the numbers using

("""\d+""".r findAllIn myStr).toList

See the Scala demo. \d+ matches one or more digits, findAllIn searches for multiple occurrences of the pattern inside a string (and also un-anchors the pattern so that partial matches could be found).

If you prefer a splitting approach, you might use

myStr.split("\\D+").filter(_.nonEmpty).toList

See another demo. Here, \D+ matches one or more non-digit chars, and these chunks are used to split on (texts between these chunks land in the result). .filter(_.nonEmpty) will remove empty items that usually appear due to matches at the start/end of the string.

edited Sep 12, 2017 at 8:42

answered Sep 12, 2017 at 8:37

Wiktor Stribiżew

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