If condition for dynamic variable in PHP

Question

I have a input checkbox field, where its name generate dynamically using JavaScript.

<input type="checkbox" name="options_'.$j.'"  class="check">

Now, I want to check whether any checkbox is checked or not in if condition. I have written the following code. But it is not working. Please help me to correct the code.

for($i = 0; $i<=1; $i++)
    {
        if(!isset($_POST['options_ '.$i]))
        {
            echo $error;
        }
        $i++;
    }

Is this is the correct format?

for($i = 0; $i<=count($_POST); $i++) { if(!isset($_POST['options_ '.$i])) { echo $error; } } — Death-is-the-real-truth
– Death-is-the-real-truth, Commented Sep 13, 2017 at 6:41
why don't you go for <input type="checkbox" name="options['.$j.']" class="check"> in your HTML, now you can use count ($_POST['options']) directly instead of this much code — Death-is-the-real-truth
– Death-is-the-real-truth, Commented Sep 13, 2017 at 7:16

caryarit ferrer · Accepted Answer · 2017-09-13 06:41:18Z

1

the $i++; is not neccesary the one in the for will do it for you

answered Sep 13, 2017 at 6:41

caryarit ferrer

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