How to convert a list [0,1,2,1] to a list of string, when we convert 0 to 'abc', 1 to 'f' and 2 to 'z'? So the output list will be ['abc','f','z','f'].
I did:
x = []
for i in xrange(input):
if input[i] == ...
x.append ('abc')
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How about use dict as a map? For example, map=dict(0='abc'), then map['0'] = 'abc'.rojeeer– rojeeer2017-09-14 15:04:22 +00:00Commented Sep 14, 2017 at 15:04
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Possible duplicate of Is a Python dictionary an example of a hash table?Aman Jaiswal– Aman Jaiswal2017-09-14 15:06:52 +00:00Commented Sep 14, 2017 at 15:06
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OP, did either of the proposed answers answer your question?RagingRoosevelt– RagingRoosevelt2017-09-20 15:12:59 +00:00Commented Sep 20, 2017 at 15:12
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2 Answers
Use a dictionary as your translation table:
old_l = [0, 1, 2, 1]
trans = {0: 'abc', 1: 'f', 2: 'z'}
Then, to translate your list:
new_l = [trans[v] for v in old_l]
Comments
As an alternative to a dict, if you can guarantee that the numbers are sequential, you can just use a list and indexes:
subs = ['abc','f','z']
original = [0, 1, 2, 1]
result = [subs[x] for x in original]
Same idea as the dict, but marginally less to type?
