Pulling python module up into package namespace

Question

If I have a directory structure like this:

package/
    __init__.py
    functions.py      #contains do()
    classes.py        #contains class A()

And I want to be able to call

import package as p

How do I make the contents of functions, classes, accessible as:

p.do()
p.A()

in stead of:

p.functions.do()
p.classes.A()

The subdivision in files is only there for convenience (allowing easier collaboration), but I'd prefer to have all the contents in the same namespace.

user395760 · Accepted Answer · 2011-01-07 11:01:22Z

15

You could do this in __init__.py (because that's what you import when you import package):

from package.functions import *
from package.classes import *

However, import * is nearly always a bad idea and this isn't one of the exceptions. Instead, many packages explicitly import a limited set of commonly-used names - say,

from package.functions import do
from package.classes import A

This too allows accessing do or A directly, but it's not nearly as prone to name collisions and the other problems that come from import *.

answered Jan 7, 2011 at 11:01

user395760

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1 Comment

noio Over a year ago

Perfect, thank you. I didn't need to import *, selecting the functions worked fine. I didn't know doing this (from B import B) would put B into the package namespace as package.B. Though it's kind of obvious now.

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