I want to get a the part of string of an email after @ using regular expression. For example, I have the string '[email protected]' and i want to get 'gmail.com'. I wrote /^@./ but doesn't work- I wrote
preg_match('/^@./', $string, $output);
print($output);
How can i fix it?
You have several mistakes. First, with the caret you're telling you want the @ symbol to be first in the string. So for an email that will never match. Then, you need to set a capturing group to actually get the part after the @. So it'd look like this:
<?php
$mail = "[email protected]";
preg_match('/@(.+)/', $mail, $output);
print_r($output[1]); // gmail.com
However, this is such a simple task that you should not use a regular expresion. explode() will do:
<?php
$mail = "[email protected]";
$mailArray = explode("@", $mail);
print_r($mailArray[1]); // gmail.com
Why regex for this kind of simple task? use strpos with the combination of substr or just used explode() with @ as first parameter as directed by other answers.
$email_string = "[email protected]";
$result = substr($email_string, strpos($email_string, "@") + 1);
echo $result ;
