PHP extract src from JavaScript string

Question

In my code I am trying to extract src value from JavaScript variable but I am literary confused because I have two src values JavaScript so I am using explode function but it doesn't extract the url properly. My main goal is to get only .mp4 url from it but I don't how to extract it. I have no problem to use regex because it simple and short but I don't know how to use for it.

Here is the my PHP Code

$b = "var myVideo=videojs('my_play');myVideo.src([{type:\"video/mp4\",src:\"https://example.com/dl/abc123/video.mp4\"}])";
$data = explode('type:"video/mp4",src:"', $b);
echo $data[1];

Echo show this value

https://example.com/dl/abc123/video.mp4"}])

Expected output:

https://example.com/dl/abc123/video.mp4

Can you share your expected output?

Sahil Gulati
– Sahil Gulati

2017-09-17 10:26:38 +00:00
Commented Sep 17, 2017 at 10:26 — Sahil Gulati
– Sahil Gulati, Commented Sep 17, 2017 at 10:26
see my updated question

Rtra
– Rtra

2017-09-17 10:29:12 +00:00
Commented Sep 17, 2017 at 10:29 — Rtra
– Rtra, Commented Sep 17, 2017 at 10:29

Community · Accepted Answer · 2020-06-20 09:12:55Z

1

Here we are using preg_match to achieve desired output.

Regex: /src\s*:\s*"\K[^"]+

1. src\s*:\s*"\K this will match src:" and \K will reset current match. Optionally we are taking care of spaces with \s*

2. [^"]+ This will match all except "

Try this code snippet here

<?php
ini_set('display_errors', 1);
$b = "var myVideo=videojs('my_play');myVideo.src([{type:\"video/mp4\",src:\"https://example.com/dl/abc123/video.mp4\"}])";
preg_match('/src\s*:\s*"\K[^"]+/', $b,$matches);
print_r($matches[0]);

edited Jun 20, 2020 at 9:12

CommunityBot

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answered Sep 17, 2017 at 10:31

Sahil Gulati

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1 Comment

Sahil Gulati Over a year ago

@Rtra Glad to help you my friend.. :)

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