for suppose if I have a list of unique elements,
list = [.......,'a','b','c',.....]
How to replace 'a','b' with 'd' such that it results,
list = [.....,'d','c'.....]
without any loops.
I have tried doing this, but it's not working.
list[list.index('a'):list.index('b')] = 'd'
A slice l[start:stop] does not include the element at the stop position.
Your code is almost correct, you only need to add 1 to list.index('b'):
In [14]: l = ['a', 'b', 'c', 'e']
In [15]: l[l.index('a'):l.index('b') + 1] = 'd',
In [16]: l
Out[16]: ['d', 'c', 'e']
Also: try to avoid using names of built-in functions and types as variable names.
You can first join the list, then use replace:
l = ["a", "d", "c", "a", "b", "c", "e"] #example list
new_list = list(''.join(l).replace("abc", "dc"))
Output:
['a', 'd', 'c', 'd', 'c', 'e']
