Using jquery, how can I select all elements that dont have attribute's value in a array of values?
Let's say I have the array ['a', 'b'] and inputs
<input value="a">
<input value="b">
<input value="c">
<input value="d">
How can I select only those with values c and d? Is there a way without each() using some kind of selector so I can use it for exampe with find(selector) function?
select all input using $('input') and then use filter()
var arr = ['a', 'b'];
var inputs = $('input').filter((x,y) => !arr.includes($(y).val()));
console.log(inputs.length);<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input value="a">
<input value="b">
<input value="c">
<input value="d">
filter() function or similar. I was only trying to mix up some selector. Thanks!You can use :not() pseudo selector
let not = ['a', 'b'];
$(`input:not([value=${not[0]}],[value=${not[1]}])`).val(1);<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js">
</script>
<input value="a">
<input value="b">
<input value="c">
<input value="d">alternatively
let not = ['a', 'b'];
$(`input:not(${not.map(prop => `[value=${prop}]`)})`).val(1);<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js">
</script>
<input value="a">
<input value="b">
<input value="c">
<input value="d">
not array , can there be a way around it
$(`input:not(${not.map(prop => `[value=${prop}]`).join(",")})`);