python from hex to shellcode format

Question

I try to convert a hex string to shellcode format For example: I have a file in hex string like aabbccddeeff11223344 and I want to convert that through python to show this exact format: "\xaa\xbb\xcc\xdd\xee\xff\x11\x22\x33\x44" including the quotes "".

My code is:

with open("file","r") as f:
    a = f.read()
    b = "\\x".join(a[i:i+2] for i in range(0, len(a), 2))
    print b

so my output is aa\xbb\xcc\xdd\xee\xff\x11\x22\x33\x44\x.

I understand I can do it via sed command but I wonder how I may accomplish this through python.

ForceBru · Accepted Answer · 2017-09-19 15:14:38Z

2

The binascii standard module will help here:

import binascii

print repr(binascii.unhexlify("aabbccddeeff11223344"))

Output:

>>> print repr(binascii.unhexlify("aabbccddeeff11223344"))
'\xaa\xbb\xcc\xdd\xee\xff\x11"3D'

answered Sep 19, 2017 at 15:14

ForceBru

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6 Comments

kluo Over a year ago

Thank you. So the output is missing \x22\x33\x44. I got the error "Type Error: Odd-length string".

ForceBru Over a year ago

@kluo, no, the output of the code in my answer is not missing anything and the code is not causing any errors. Please double-check how you run it and keep in mind that '\x44' == 'D', '\x33' == '3' and '\x22' == '"', which is exactly what this code produces.

kluo Over a year ago

Oh I see. Can we keep the original hex format somehow?

ForceBru Over a year ago

@kluo, I believe there's no need to: the compiler will deal with the mix of hex-escapes and literal ASCII characters just fine. They are the same thing.

kluo Over a year ago

I have put aabbccddeeff11223344 to a file call 'test': and following code: import binascii with open ("test","r") as f: a = f.read() b = repr(binascii.unhexlify(a)) print b and I got TypeError: Odd length string. That's weird

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