Python: check string using re.match

Question

I need to write func to check str. If should fit next conditions:

1) str should starts with alphabet - ^[a-zA-Z]

2) str may contains alphabet, numbers, one . and one -

3) str should ends with alphabet or number

4) length of str should be from 1 to 50

def check_login(str):
    flag = False
    if match(r'^[a-zA-Z][a-zA-Z0-9.-]{1,50}[a-zA-Z0-9]$', str):
        flag = True
    return flag

But it should mean that it starts with alphabet, length of [a-zA-Z0-9.-] is more than 0 and less 51 and it ends with [a-zA-Z0-9]. How can I limit quantity of . and - and write length's limit to all expression?

I mean that a - should returns true, qwe123 also true.

How can I fix that?

Jan · Accepted Answer · 2017-09-19 20:42:18Z

2

You will need lookaheads:

^                              # start of string
    (?=^[^.]*\.?[^.]*$)        # not a dot, 0+ times, a dot eventually, not a dot
    (?=^[^-]*-?[^-]*$)         # same with dash
    (?=.*[A-Za-z0-9]$)         # [A-Za-z0-9] in the end
    [A-Za-z][-.A-Za-z0-9]{,49} 
$

See a demo on regex101.com.

Which in Python might be:

import re

rx = re.compile(r'''
^                        # start of string
    (?=^[^.]*\.?[^.]*$)  # not a dot, 0+ times, a dot eventually, not a dot
    (?=^[^-]*-?[^-]*$)   # same with dash
    (?=.*[A-Za-z0-9]$)   # [A-Za-z0-9] in the end
    [A-Za-z][-.A-Za-z0-9]{,49} 
$
''', re.VERBOSE)

strings = ['qwe123', 'qwe-123', 'qwe.123', 'qwe-.-123', '123-']

def check_login(string):
    if rx.search(string):
        return True
    return False

for string in strings:
    print("String: {}, Result: {}".format(string, check_login(string)))

This yields:

String: qwe123, Result: True
String: qwe-123, Result: True
String: qwe.123, Result: True
String: qwe-.-123, Result: False
String: 123-, Result: False

edited Sep 19, 2017 at 20:42

answered Sep 19, 2017 at 20:20

Jan

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8 Comments

CristiFati Over a year ago

.123 (and the family) ?

Jan Over a year ago

@CristiFati: Updated the demo link (wrong version linked, initially).

Petr Petrov Over a year ago

But if I check one alphabet symbol for example q it returns False, but it should returns True

CristiFati Over a year ago

I'm being picky, but \w allows _ :). Anyway, nice answer.

Jan Over a year ago

@CristiFati: Right you are, one needs to write it out in full if this matters.

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