VB.NET: How to incrementally replace values in String Array

Question

I have a String array with the following values:

dim strArray() as string  
dim newValueFor0Index as string = "Z"  
strArray(0) = "A"  
strArray(1) = "B"  
strArray(2) = "C"`

what i need is a loop or something to replace the values as such:

strArray(0) = "Z"  
strArray(1) = "A"  
strArray(2) = "B"`

I then need to add another index to the strArray() which will hold the last value ie:

strArray(0) = "Z"  
strArray(1) = "A"  
strArray(2) = "B"  
strArray(3) = "C"`

I tried a while loop :

while i < Count

    ni++  
    currentArr(ni) = currentArr(i)  
    i++  
end while

but this won't work because i am using redundant values

Hans Passant · Accepted Answer · 2011-01-09 18:29:39Z

4

An array is simply the wrong collection type to do this. It is trivial with a list:

    Dim lst As New List(Of String)
    lst.Add("A")
    lst.Add("B")
    lst.Add("C")
    lst.Insert(0, "Z")

You can always whack it back to an array, if really necessary:

    Dim array() As String = lst.ToArray()

answered Jan 9, 2011 at 18:29

Hans Passant

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5 Comments

the array is coming from a cookie and i am putting it into an array by doing... strArray = cookieValue.split("$")

also if i do as you advise won't the values of the list be Z, B, C? when i need it to be Z, A, B, C

Dim lst As New List(Of String)(cookieValue.Split("$"c)). No, Insert really does insert, not replace.

what does the c signify here?"$"c

@kevon: It's a cast to char. You might want to turn Option Strict to On. Will save you headache if it comes to casting.