Converting Javascript Object into PHP array [duplicate]

Question

I send this Javascript array into PHP page using form submit {"1":"2","2":"2","3":"2","4":"2"}

Now, I want to convert this array into PHP array, like this

$cars = array("Volvo", "BMW", "Toyota");

So, this is what I tried:

$phparray = str_replace(':', ',', $_POST["questionandanswers"]); // Remove : and replace it with ,
$phparray = str_replace('}', '', $phparray); // Remove }
$phparray = str_replace('{', '', $phparray); // Remove {
echo '<br/>';
echo $phparray; // Output of this is: "1","2","2","2","3","2","4","2"



$questionandanswers = array($phparray); // Now convert it into PHP array

But it is not working. Looks like i cannot put $phparray variable here array($phparray)

But, If instead of putting $phparray variable in array($phparray), If i put the output of $phparray manually, then, it works like: array("1","2","2","2","3","2","4","2")

What's the solution?

That's not a "Javascript array", that's JSON.

Andreas
– Andreas

2017-10-07 08:07:46 +00:00
Commented Oct 7, 2017 at 8:07 — Andreas
– Andreas, Commented Oct 7, 2017 at 8:07
json_decode($json)

Progrock
– Progrock

2017-10-07 08:07:48 +00:00
Commented Oct 7, 2017 at 8:07 — Progrock
– Progrock, Commented Oct 7, 2017 at 8:07

Sara Yusri · Accepted Answer · 2022-03-25 10:30:51Z

8

It seems that your form submits a json object to the server so use json_decode with second parameter set to true to convert it to an array.

$php_array=  json_decode($_POST["questionandanswers"],true)

edited Mar 25, 2022 at 10:30

Sara Yusri

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answered Oct 7, 2017 at 8:21

Osama

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3 Comments

Josh Poor Over a year ago

Thanks, but the thing here is, the object name is not always in a serial order: It can also be like Array ( [3] => 0 [6] => 0 [7] => 0 [11] => 0 ) . So, how to access the object, without knowing it's name?

Osama Over a year ago

Just use foreach loop with if statment according to your condition.

Josh Poor Over a year ago

Btw, you misspelled json_decode

Community · Accepted Answer · 2023-11-17 20:18:02Z

1

Use json_decode like json_decode($json). It will return an object. If you want array, use json_decode($json, true). See: https://www.php.net/manual/en/function.json-decode.php

edited Nov 17, 2023 at 20:18

CommunityBot

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answered Oct 7, 2017 at 8:12

Arka Roy

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