I am trying to check the text in my created array, if I am not using "if" every thing works and i can use "echo" but when I add the "if" command I get "wrong syntax"
@echo off
setlocal ENABLEDELAYEDEXPANSION
set i=0
for /f "delims= " %%a in ('command') do (
set /A i+=1
set list[!i!]=%%~a
)
set Filesx=%i%
rem Display array elements
for /L %%i in (1,1,%Filesx%) do (
if list[%%i] =="some ttext"
echo !list[%%i]!
)
I would consider changing your script accordingly:
@Echo Off
SetLocal EnableDelayedExpansion
Set "i=0"
For /F %%A In ('command') Do (Set/A i+=1
Set list[!i!]=%%~A)
Rem Display array elements
For /L %%A In (1,1,%i%) Do If /I "!list[%%A]!"=="some ttext" Echo !list[%%A]!
Pause
In your script you needed to change if list[%%i] to If /I "!list[%%i]!"
@echo off
setlocal ENABLEDELAYEDEXPANSION
set i=0
for /f "delims= " %%a in ('command') do (
set /A i+=1
set list[!i!]=%%~a
)
set Filesx=%i%
rem Display array elements
for /L %%i in (1,1,%Filesx%) do (
if /i "!list[%%i]!" =="some ttext" (
echo !list[%%i]!
)
)
An if statement requires an exact match (for == or equ) so if you quote one side, you need to quote the other.
also, the action for the if-true condition must be on the same physical line as the if
echo !list[%%i]!command, too?