I'm trying to program a loop with a asynchronous part in it. I dont want to wait for this asynchronous part every iteration though. Is there a way to not wait for this function inside the loop to finish?
In code (example):
import time
def test():
global a
time.sleep(1)
a += 1
test()
global a
a = 10
test()
while(1):
print a
You can put it in a thread. Instead of test()
from threading import Thread
Thread(target=test).start()
print("this will be printed immediately")
To expand on blue_note, let's say you have a function with arguments:
def test(b):
global a
time.sleep(1)
a += 1 + b
You need to pass in your args like this:
from threading import Thread
b = 1
Thread(target=test, args=(b, )).start()
print("this will be printed immediately")
Note args must be a tuple.
A simple way is to run test() in another thread
import threading
th = threading.Thread(target=test)
th.start()
You should look at a library meant for asynchronous requests, such as gevent
Examples here: http://sdiehl.github.io/gevent-tutorial/#synchronous-asynchronous-execution
import gevent
def foo():
print('Running in foo')
gevent.sleep(0)
print('Explicit context switch to foo again')
def bar():
print('Explicit context to bar')
gevent.sleep(0)
print('Implicit context switch back to bar')
gevent.joinall([
gevent.spawn(foo),
gevent.spawn(bar),
])
use thread. it creates a new thread in that the asynchronous function runs
https://www.tutorialspoint.com/python/python_multithreading.htm
time.sleepis blocking.