I have a tuple a = (('1414', 'A'), ('1416', 'B')) and I need to obtain the result as result = ((1414, 'A'), (1416, 'B')).
I tried tuple([map(int, x[0]) for x in a]) based on How to convert strings into integers in Python? and I get the result as ([1414], [1416]). How would I maintain the result as a tuple with the changed value instead of making it as a list?
Using a generator expression:
a = (('1414', 'A'), ('1416', 'B'))
result = tuple((int(x[0]), x[1]) for x in a)
Using map:
azip = list(zip(*a))
out = list(zip(map(int, azip[0]), azip[1]))
You can use a lambda in map() which converts the first element in the tuple to an int.
a = (('1414', 'A'), ('1416', 'B'))
result = tuple(map(lambda x: (int(x[0]), x[1]), a))
You can do :
print(tuple([(int(i[0]),i[1]) for i in a]))
for detailed solution :
a = (('1414', 'A'), ('1416', 'B'))
new_list=[]
for i in a:
new_list.append((int(i[0]),i[1]))
print(tuple(new_list))
b = ('1414', 'A')into1414? It would just beint(b[0]), right? No reason to usemap? So, what happens if you then try applying that logic to the overall tuple of tuples? BTW, the described output does not match; in 2.x it would result in([1, 4, 1, 4], [1, 4, 1, 6]), and in 3.x the result is a pair ofmapobjects. Considering the 2.x result carefully makes it clear where the fault is. But at any rate, this problem is caused by a typo and/or not reproducible.