Array Search over Array of objects - Javascript

You can use Array.prototype.map() MDN with normal function or arrow function.

The map() method creates a new array with the results of calling a provided function on every element in the calling array.

Noraml Map without ES6

var arr = ['0333', '0444', '0334'],
    objArray = [{
            'name': 'abc',
            'phone': '0333'
        },{
            'name': 'xyz',
            'phone': '0334'
        },{
            'name': 'fgfh',
            'phone': '0999'
        },{
            'name': 'abc',
            'phone': '0666'
        },{
            'name': 'abc',
            'phone': '0444'
        }
    ];
var rec='',res = arr.map(function(val){
    rec = objArray.find(function(obj){return obj.phone == val});
    if (rec) {
        return rec;
    }
});
console.log(res);

In ES6

const arr = ['0333', '0444', '0334'],
    objArray = [{
            'name': 'abc',
            'phone': '0333'
        },{
            'name': 'xyz',
            'phone': '0334'
        },{
            'name': 'fgfh',
            'phone': '0999'
        },{
            'name': 'abc',
            'phone': '0666'
        },{
            'name': 'abc',
            'phone': '0444'
        }
    ];
let res = arr.map(val => {
    let rec = objArray.find(obj => obj.phone == val);
    if (rec) {
        return rec;
    }
});
console.log(res);

function SearchArray() {
    var arr = ['0333', '0444', '0334'];
    var objArray = [{ 'name': 'abc', 'phone': '0333' },
    { 'name': 'fgfh', 'phone': '0999' },
    { 'name': 'abc', 'phone': '0666' },
    { 'name': 'abc', 'phone': '0444' }
    ];

    var matchingArray = [];
    var noMatchingArray = [];
    for (var i = 0; i < arr.length; i++) {
        var isFound = false;
        for (var j = 0; j < objArray.length; j++) {
            if (objArray[j]['phone'] == arr[i]) {
                matchingArray.push(objArray[j]);
                isFound = true;
                break;
            }
        }
        if (!isFound)
        {
            noMatchingArray.push(arr[i]);
        }
    }
}

First of all, modify your existing loops and add a break statement. If I do not misunderstand the purpose of your match algorithm, you want to stop looking for a match for this phone number, if you have already matched.

Moreover, I think you have an error in your code. You do not want to push the objArray in the matchingArray, right? Just the matchedObject -> j

Answering your question. I would work with a second loop looking over all objects in the objArray, pushing those who are not in the array matchingArray to the noMatchingArray.

var matchingArray = [];
    var noMatchingArray = [];
    for (var i = 0; i < arr.length; i++) {
            for (var j = 0; j < objArray.length; j++) {
                if(objArray[j]['phone'] == arr[i]){
                    matchingArray.push(objArray[j]);
                    break;
                 }
            }
    }

   for (var j = 0; j < objArray.length; j++) {
       var marked = false;
       for (var i = 0; i < matchingArray.length; i++) {
           if (objArray[j] === matchingArray[i]) {
               marked = true;
               break;
           }
       }
       if(!marked){
           noMatchingArray.push(objArray[j]);
       }
   }

even better: combining both loops back together while switching inner and outer look of your initial algorithm makes it even more readable and faster than my first solution.

var matchingArray = [];
var noMatchingArray = [];
for (var j = 0; j < objArray.length; j++) {
    var marked = false;
    for (var i = 0; i < arr.length; i++) {
            if(objArray[j]['phone'] == arr[i]){
                matchingArray.push(objArray[j]);
                marked = true;
                break;
             }
    }
    if(!marked){
       noMatchingArray.push(objArray[j]);
   }
}