Python struct with large list

Question

Im trying to convert my very long integer list i a binary array (list) Im using struct.pack() and it works well but i think this is very ugly:

buf = pack(">IIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIII", *data)

I need to do this because my list has 113 Items with large and small values. Is there a option to use pack() with a long list without having 113 "I"'s?

willeM_ Van Onsem · Accepted Answer · 2017-10-13 13:19:55Z

4

If you multiply a string with an integer, the string is repeated that many times. For instance:

>>> 'foo'*3
'foofoofoo'

So you can use:

buf = pack(">" + "I"*len(data), *data)

This is more elegant and safe as well: in case the number of objects changes, this will simply keep working.

answered Oct 13, 2017 at 13:19

willeM_ Van Onsem

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