Sorting multiple array objects with different keys

Question

Before, I was combining 2 arrays into one array and using sort(), I was able to sort them by created_at.

let result = [...item.messages, ...item.chat_messages]
result.sort((a, b) => new Date(b.created_at) - new Date(a.created_at))
item.messages = result

Now, I am in another scenario. I want to add one more array (sms_messages) into this array and however want it to order by its scheduled_at field.

Is it possible to achieve it with this approach?

let result = [...item.messages, ...item.chat_messages, ...item.sms_messages]
// and order by messages' and chat_messages' created_at (like above) together as 
// sms_messages' sheduled_at

@OriDrori, yes. Others should use created_at like before but sms needs to use scheduled_at. So I can give a list in related order — senty
– senty, Commented Oct 14, 2017 at 17:34
Please provide an actual complete example of the data structure you want to work with. It's hard to discern from your description. — Michael Geary
– Michael Geary, Commented Oct 14, 2017 at 17:39

trincot · Accepted Answer · 2017-10-14 17:35:25Z

1

You could use || to get the first of both properties it finds to be there, assuming that each object has at least one of both properties, but scheduled_at gets precedence:

result.sort((a, b) => 
    new Date(b.scheduled_at || b.created_at) - new Date(a.scheduled_at || a.created_at))

answered Oct 14, 2017 at 17:35

trincot

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3 Comments

senty Over a year ago

That seems like a good approach, however sms has created_at property as well as scheduled_at and I think it is ordering by created_at rather than scheduled at

trincot Over a year ago

That should not be the case: scheduled_at is taken if it exists before falling back to created_at. If an object has both properties, scheduled_at will be used.

senty Over a year ago

Yes, I am sorry. It is working like charm! Thanks a million

cyr_x · Accepted Answer · 2017-10-14 17:56:22Z

0

Just check which which property exists and use it to sort the objects.

const sortByDate = props => {
  return (a, b) => {
    let propA = props.find(p => a.hasOwnProperty(p));
    let propB = props.find(p => b.hasOwnProperty(p));
    if(!propA || !propB) return 0;
    return new Date(b[propB]) - new Date(a[propA]);
  };
}

result.sort(sortByDate(['scheduled_at', 'created_at']));

edited Oct 14, 2017 at 17:56

answered Oct 14, 2017 at 17:45

cyr_x

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2 Comments

senty Over a year ago

But sms_messages has both properties scheduled_at and created_at. I think this won't solve this because of it

cyr_x Over a year ago

In my example it prioritises the scheduled_at attribute and then falls back to created_at. So if scheduled_at is present on the object it will get sorted by sheduled_at.

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