How to generate a unique id for same input id using Python?

Question

I have a list of ids and I want to display a fake id for each id in my list using Python.

I used the uuid1() but when there is a duplicated id in my list the program stop and don't generate the same random id for same input id.

 print uuid.uuid1(data['user']['id']).int>>64

It doesn't work for me. uuid4() is even worse it doesn't generate anything. — Brenna
– Brenna, Commented Oct 15, 2017 at 8:51

Loïc · Accepted Answer · 2017-10-15 09:07:12Z

1

You could just hash your id :

import hashlib
id = 12
hashlib.sha256(str(id).encode()).hexdigest() # with python2.x you don't need to encode()
# => '6b51d431df5d7f141cbececcf79edf3dd861c3b4069f0b11661a3eefacbba918'

You'll have to store the correspondance somewhere though, because there is no way to retrieve the id from a hash.

answered Oct 15, 2017 at 9:07

Loïc

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3 Comments

Brenna Over a year ago

Thank you for your help. This solution worked for me but it's too long. Do you know how to shorten or convert to integer?

Loïc Over a year ago

you could use md5 instead of sha256, md5 are only 32 chars long. Check this : en.wikipedia.org/wiki/List_of_hash_functions

Brenna Over a year ago

Thank you @Loïc, it's perfect now !

Francois Mockers · Accepted Answer · 2017-10-15 08:58:52Z

1

from python uuid doc, uuid1 is dependent on current time.

You could use uuid3 to have a reproducible uuid for the same input, by reusing the same namespace:

namespace = uuid.uuid4()
...
print uuid.uuid3(namespace, "1")

answered Oct 15, 2017 at 8:58

Francois Mockers

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