I am trying to execute this code but its giving me random values everytime:
Output:
Code:
public class Temp {
static int x;
static {
try {
x = System.in.read();
} catch (IOException ex) {
System.out.println(ex);
}
}
}
class TempA {
public static void main(String[] args) {
System.out.println(Temp.x);
}
}
The values aren't random, they're:
[...] the next byte of data from the input stream. The value byte is returned as an int in the range 0 to 255. If no byte is available because the end of the stream has been reached, the value -1 is returned. http://docs.oracle.com/javase/7/docs/api/java/io/InputStream.html#read()
This means if you type a and hit Enter you'll get 97.
If you're looking for content of what was typed (and not the raw byte value) you'll need to make some changes... The easiest way it to use the Scanner class. Here's how you get a numerical value:
import java.util.Scanner;
public class Temp {
static int x;
static {
Scanner sc = new Scanner(System.in);
x = sc.nextInt();
}
}
class TempA {
public static void main(String[] args) {
System.out.println(Temp.x);
}
}
See also System.in.read() method.
This is because it is returnung the ASCII value of the first digit/character of your input.
System.in stream is typically being feed from the console/shell, it is usually typed text. There is no text but encoded text. The shell is using whatever character encoding it is using, and that's typically UTF-8, or CP437 or similar, not ASCII. Go locale or chcp to find yours.
System.in.read()returns the next byte currently stored inSystem.in. This object usually is connected to your standard input, the console for example. So if your typing something into the keyboard it will get stored there. So I would assume that if you type in5it will also print5.