How to pass parameter using select in bash

Question

I'm trying to create a bash script that lets the user use both a menu style and also a command line switch style interface. I was wondering if there was a way to pass a parameter to a menu option in select as if it were just an argument to a script. For example, in my script I can specify a file to move to my junk folder by saying junk -d file.txt. But if the user does not specify any params it should use the select option. i.e. 1) move file 2) clear junk folder 3) watch folder etc.

On this menu, I want to be able to write the option and then send an argument to that option. Like 1 filetobemoved.txt. I have tried putting $OPTARG after the method that gets called by the menu but this doesn't seem to work.

Here is the code I have for the menu at the moment, I'm trying to call the recover method and pass an argument (the filename) to it.

if (( $# == 0 ))
then if (( $OPTIND == 1 )) 
 then select menu_list in list recover delete total watch kill exit
     do case $menu_list in
     "list") list;;
     "recover") recover $GETOPT;;
     "delete") delete;;
     "total") total;;
     "watch") _watch;;
     "kill") _kill;;
     "exit") exit 0;;
     *) echo "unknown option";;
     esac
  done
fi

Thanks for any help.

Barmar · Accepted Answer · 2017-10-17 19:16:14Z

2

Put the code that executes the cases in a function. Then you can check for the command line option and skip the select, and just call the function.

do_command() {
    case "$1" in
     "list") list;;
     "recover") recover $GETOPT;; # had -a after recover
     "delete") delete;;
     "total") total;;
     "watch") _watch;;
     "kill") _kill;;
     "exit") exit 0;;
     *) echo "unknown option";;
    esac
}
if (($# == 0))
then if (( $OPTIND == 1 )) 
    then select menu_list in list recover delete total watch kill exit
         do do_command "$menu_list"
         done
    fi
elif [[ "$1" = "-d" ]]
then do_command delete
...
fi

answered Oct 17, 2017 at 19:16

Barmar

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