PHP: compare arrays by values return keys of different

Question

Probably a duplicate...

Array1 = ['a'=>1, 'b'=>2, 'c'=>3];
Array1 = ['a'=>1, 'b'=>2, 'c'=>'anaconda'];
$keys = ISTHEREAFUCNTION(array1, array2);

echo ($keys);

// c

Is there a function that compares arrays by value and return keys of array1 values different from values of array2?

I can do it just iterating over both arrays, but maybe there is a more elegant solution?

Thank you!

Google: php array difference. php.net/manual/en/function.array-diff.php — tereško
– tereško, Commented Oct 18, 2017 at 9:06

Akshay Hegde · Accepted Answer · 2017-10-18 09:07:38Z

1

Using array_diff() and array_keys()

$ cat test.php
<?php

$arr1 = ['a'=>1, 'b'=>2, 'c'=>3];
$arr2 = ['a'=>1, 'b'=>2, 'c'=>'anaconda'];
print_r(array_keys(array_diff($arr1,$arr2)));

?>

$ php test.php
Array
(
    [0] => c
)

answered Oct 18, 2017 at 9:07

Akshay Hegde

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1 Comment

Sergej Fomin Over a year ago

thank you! feel stupid now) I thought that array_diff returns only diff.values, and re-writes the keys:)

Xyz · Accepted Answer · 2017-10-18 09:08:32Z

0

Use array_keys and array_diff_assoc

array_keys(array_diff_assoc($array1, $array2));

answered Oct 18, 2017 at 9:08

Xyz

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