The below code takes the first two character of string and check if pattern is "de" or None it returns None else it returns the Test("Found")
val s =Option("abc")
val t = s.map(_.take(2))
case class Test(id:String)
t match {
case Some("de") => None
case None => None
case _ => Test("Found")
}
Can anyone suggest a efficient solution for case matching
I think I get what you're asking so let me try this:
val condition = Option("abc").exists(_.toLower.take(2) == "de")
val output: Any = if(condition) Test("found") else None
The first portion returns false if the Option is None. It also returns false if the first two letters of the string are "de" in a case insensitive way.
The second portion returns either a None or a Test object. However, I want to point out that this results in an Any. Did you mean for it to return a Option[Test] type instead?
Option[Test] not AnyI assume, you meant Some(Test("Found")) in the last line of your snippet, judging from your comment to the other answer.
If so, this is what you are looking for:
t.filterNot(_.take(2) == "de").map(_ => Test("Found"))
