PUNCTUATION = '''!"#$%&'()*+,-./:;<=>?@[\]^_`{|}~'''
WHITE_SPACE = ' \t\n\r\v\f'
EXTRANEOUS = PUNCTUATION + WHITE_SPACE
str = ["HeLlo!!!,","H%I"]
l = []
for s in str:
for x in EXTRANEOUS:
sd = s.replace(x,"")
l.append(sd)
print(l)
Hi! My python code is not working for some reason. I'm trying to get rid of any punctuation mark and white space.
Your code wipes out the result of previous replacements.
for s in str:
for x in EXTRANEOUS:
s = s.replace(x,"")
l.append(s)
Just use re.sub:
import re
str = ["HeLlo!!!,","H%I"]
final_str = [re.sub('\W+', '', i) for i in str]
Output:
['HeLlo', 'HI']
You always use the unmodified version s of your strings. Just replace sd with s:
PUNCTUATION = '''!"#$%&'()*+,-./:;<=>?@[\]^_`{|}~'''
WHITE_SPACE = ' \t\n\r\v\f'
EXTRANEOUS = PUNCTUATION + WHITE_SPACE
str = ["HeLlo!!!,","H%I"]
l = []
for s in str:
for x in EXTRANEOUS:
s = s.replace(x,"")
l.append(s)
print(l)
You can do it like this:
PUNCTUATION = '''!"#$%&'()*+,-./:;<=>?@[\]^_`{|}~'''
WHITE_SPACE = ' \t\n\r\v\f'
EXTRANEOUS = PUNCTUATION + WHITE_SPACE
str_list = ["HeLlo!!!","H%I"] # this a list
result = []
for s in str_list:
l = ""
for x in s:
if x not in EXTRANEOUS:
l += x
result.append(l)
print(result)
Output:
['HeLlo', 'HI']
As others have said, you are not storing the output of the replace() function in s. Just replace sd = s.replace(x,"") with s = s.replace(x,"") and l.append(s). One more way to remove punctuation is to do like this .
Python 2.x:
import string
stri = ["HeLlo!!!,","H%I"]
l = []
for s in stri:
l.append(s.translate(None, string.punctuation))
print(l)
Python 3.x
import string
stri = ["HeLlo!!!,","H%I"]
l = []
for s in stri:
l.append(s.translate(str.maketrans("","", string.punctuation)))
print(l)
Output:
['HeLlo', 'HI']
