I wonder how to solve the following problem: I want to get access to one value based on a pair of values, so e.g. for values 0 and 1 I want to get 3, for 4 and 5 I want to get 2, etc. I was thinking about declaring 3 dimensional array. Is there any better way to achieve this? If not, how can I declare 3d array in ObjectiveC?
Thanks!
If you want results based on pairs of values (rather than triples), then you want a 2D array.
Usually, 2D arrays are just arrays of arrays. If you want to use Obj-C's NSArray object, then you'd just do something like this:
NSArray* yCoord1 = [NSArray arrayWithObjects:@"oneValue", @"secondValue", nil];
NSArray* yCoord2 = [NSArray arrayWithObject:@"thirdValue"];
NSArray* array = [NSArray arrayWithObjects:yCoord1,yCoord2,nil];
Then, to access the array:
NSUInteger xCoord = 0;
NSUInteger yCoord = 1;
[[array objectAtIndex:xCoord] objectAtIndex:yCoord]; //Result: @"secondValue"
It's also possible to use plain C arrays in this way; google "2D C arrays" for tons of tutorials if you'd prefer that.
If you are going to have a value for most or every possible pair and are storing only integer values (as it seems from your example), a real C array might well meet your needs best, because you can quickly index into a 3D array to get what you are looking for.
If it's a sparse set of data, I can see something like what you are doing working out better if you concatenate your two key values together into something like "1-Firstval;2-SecondVal" and hold the numbers you are looking for in an NSDictionary. Then you still get a fast lookup without using a lot of memory.
