Is it possible to have a variable be defined as two different things without using an array?
So for example:
var myVar = "asd" || "fgh" // or maybe it's "asd" && "fgh"?
var message = "asdtest"
var otherMessage = "fghtest"
if (message === myVar + "test") {
console.log("success!")
}
else if (otherMessage === myVar + "test") {
console.log("success!")
}
No, a variable can only hold a single thing at a time. If you want multiple things, you should use an array.
var myVar = "asd" || "fgh"
This line of code will evaluate "asd" to see if it is 'truthy', and it is. Therefore, myVar is set to "asd". If instead it were 'falsy', for example if you did var myVar = null || "fgh", then it would set myVar to the second part, thus making it equal "fgh".
This is just one definition. The variable will be assigned to the value of the expression on the right side. In principle, this is the same thing as
var x = 1 + 2;
How || works is that it is logical OR: It returns the first "truthy" value (such as a non-empty String, all values are truthy unless they are false, 0, "", null, undefined, or NaN). This is useful if you want to give defaults to "missing" values for example:
var size = specifiedSize || 100;
In your case, it is simply asd.
A variable can only hold a single value. However, your variable can be referencing an array or an object, which can hold more than one value.
You may use objects or arrays to store all possible values:
var myVarObj = {
p1: "asd"
p2: "fgh"
};
var myVarArr = ["asd", "fgh"];
for (var property in myVarObj) {
if (message === myVarObj[property] + "test") {
console.log("success!");
}
}
for (var value in myVarArr) {
if (message === value + "test") {
console.log("success!");
}
}
You can use a function expression
var myVar = bool => bool ? "asd" : "fgh";
console.log(myVar(1)); // `"asd"`
console.log(myVar(0)); // `"fgh"`